Maldaru Lake
Maldaru lake is one of the highest located lake from sea level in India. It’s situated at an altitude of 15,500 ft at south east of Osla village in Harkidhun (Har ki Doon) valley.
The Maldaru Tal Trek is a summer delight that will leave you struck by awe because of the gorgeousness of the gigantic Himalayan valley. Maldaru is a glacial lake and is about 300m long. The people of Osla village consider Maldaru Tal to have auspicious waters. It is situated in Sankri range of Uttarkashi district of Uttarakhand.
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| Cost Per Person ₹19999 + 5% GST |
Duration 8 Days |
Trek Distance 64 Km |
| Trek Altitude 14,350 Feet. |
Group Size 12 |
Best Time Summer, Autumn |
| Trek PDF |
Short Itinerary
Day 1: Dehradun. Drive to Sankri.
Distance: 180 km
Duration: 8-9 hour drive
Day 2: Drive from Sankri to Taluka to Dharkot
Altitude: 6955 ft to 8380 ft
Distance: 12 km drive. 9 km trek
Duration: 6-7 hrs.
Day 3: Dharkot to Batgair
Altitude: 8380 ft to 10722 ft
Distance: 5.5 km
Duration: 4-5 hours
Day 4: Batgair to Rashi
Altitude: 10,722 ft to 12,250 ft
Distance: 6 km
Duration: 5-6 hrs.
Day 5: Rashi to Maldaru Base Camp
Altitude: 12250 ft to 13188 ft
Distance: 6 km
Duration: 5-6 hrs.
Day 6: Maldaru Base camp to Maldaru Lake and back to Seema
Altitude: 13188 ft to 14,338 ft to 8,390ft
Distance: 4 km to the lake + 8 km to Seema
Duration: 4-5 hrs for the lake + descent to Seema is another 4-5 hours.
Day 7: Seema to Taluka to Sankri
Altitude: 8,390 ft to 6955 ft to 6400 ft
Distance: 12 km trek + 12 km drive
Duration: 5- 7 hrs.
Day 8: Sankri to Dehradun
Distance: 180 km drive
Duration: 8-9 hour
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